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5w^2-11=22-4w
We move all terms to the left:
5w^2-11-(22-4w)=0
We add all the numbers together, and all the variables
5w^2-(-4w+22)-11=0
We get rid of parentheses
5w^2+4w-22-11=0
We add all the numbers together, and all the variables
5w^2+4w-33=0
a = 5; b = 4; c = -33;
Δ = b2-4ac
Δ = 42-4·5·(-33)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{676}=26$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-26}{2*5}=\frac{-30}{10} =-3 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+26}{2*5}=\frac{22}{10} =2+1/5 $
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